vi p = {1, 2, 3, 5, 7, 13, 17, 19, 31, 61, 89, 107, 127, 521, 607, 1279, 2203, 2281, 3217, 4253, 4423, 9689,
9941, 11213, 19937, 21701, 23209, 44497, 86243, 110503, 132049, 216091, 756839, 859433, 1257787, 1398269, 2976221, 
3021377, 6972593, 13466917, 20996011, 24036583};
using Z = Mint<1000000007>;
void solve()
{
  int n;
  cin >> n;

  cout << power<Z>(2, p[n] - 1) - 1 << '\n';
}